Martes, Setyembre 4, 2012

Examples:

a. Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of 444 m/s in 1.8 seconds, then what is the acceleration and what is the distance that the sled travels?

Solution:

Given:
vi = 0 m/s
vf = 44 m/s
t = 1.80 s
Find:
a = ??
d = ??

a = (Delta v)/t
a = (444 m/s - 0 m/s)/(1.80 s)
a = 247 m/s2
d = vi*t + 0.5*a*t2
d = (0 m/s)*(1.80 s)+ 0.5*(247 m/s2)*(1.80 s)2
d = 0 m + 400 m
d = 400 m
(Note: the d can also be calculated using the equation vf2 = vi2 + 2*a*d)

b. An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.

Solution:

Given:
a = +3.2 m/s2
t = 32.8 s
vi = 0 m/s
Find:
d = ??

d = vi*t + 0.5*a*t2
d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s2)*(32.8 s)2
d = 1720 m

c. Upton Chuck is riding the Giant Drop at Great America. If Upton free falls for 2.6 seconds, what will be his final velocity and how far will he fall?

Solution:

Given:
a = -9.8 m
t = 2.6 s
vi = 0 m/s
Find:
d = ??
vf = ??

d = vi*t + 0.5*a*t2
d = (0 m/s)*(2.6 s)+ 0.5*(-9.8 m/s2)*(2.6 s)2
d = -33 m (- indicates direction)
vf = vi + a*t
vf = 0 + (-9.8 m/s2)*(2.6 s)
vf = -25.5 m/s (- indicates direction)






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